Vibrational Spectroscopy: Unveiling Molecular Fingerprints
Vibrational spectroscopy encompasses techniques that study the vibrations of molecules. When molecules absorb energy corresponding to specific vibrational frequencies, they transition to higher vibrational energy levels. These transitions provide a unique “fingerprint” of the molecule, offering profound insights into its structure, bonding, and functional groups. The two primary techniques in vibrational spectroscopy are Infrared (IR) Spectroscopy and Raman Spectroscopy.
What are Molecular Vibrations?
At temperatures above absolute zero, molecules are not static entities; their atoms are constantly oscillating around their equilibrium positions. These oscillations are known as molecular vibrations. These vibrations are quantized, meaning they can only occur at specific discrete energy levels.
Molecules exhibit various types of vibrations, primarily classified as:
- Stretching Vibrations: Involve a rhythmic movement along the bond axis, increasing and decreasing the bond length.
- Symmetric stretching: Both bonds stretch or compress simultaneously.
- Asymmetric stretching: One bond stretches while the other compresses.
- Bending Vibrations: Involve a change in the angle between bonds or the movement of a group of atoms with respect to the rest of the molecule, without changing bond lengths.
- Scissoring (or Bending): Two atoms move towards and away from each other, closing and opening the angle.
- Rocking: A group of atoms moves back and forth in the same plane.
- Wagging: A group of atoms moves out of the plane, either above or below.
- Twisting: A group of atoms rotates around a bond, with one atom moving up and another down relative to a plane.
Degrees of Freedom and Normal Modes
The total number of possible independent motions (degrees of freedom) for a molecule with N atoms is 3N. These degrees of freedom include translational, rotational, and vibrational motions.
- Translational Degrees of Freedom: 3 (movement along x, y, z axes).
- Rotational Degrees of Freedom: 3 for non-linear molecules, 2 for linear molecules.
- Vibrational Degrees of Freedom (Normal Modes):
- For non-linear molecules: 3N−6
- For linear molecules: 3N−5
- For non-linear molecules: 3N−6
Each of these vibrational degrees of freedom corresponds to a normal mode of vibration, which is an independent, characteristic vibration of the molecule. Each normal mode has a specific energy and frequency.
The Harmonic Oscillator Model
As a first approximation, molecular vibrations can be modeled using the harmonic oscillator model. In this model, the bond is treated as a perfect spring, and the atoms oscillate symmetrically about their equilibrium positions.
The potential energy (V) of a harmonic oscillator is given by: V(x)=21kx2 where k is the force constant (a measure of bond stiffness) and x is the displacement from equilibrium.
The energy levels (Ev) for a quantum mechanical harmonic oscillator are: Ev=(v+21)hν0 where:
- v is the vibrational quantum number (v=0,1,2,…).
- h is Planck’s constant.
- ν0 is the fundamental vibrational frequency, given by: ν0=2π1μk where μ is the reduced mass of the vibrating system (μ=m1+m2m1m2 for a diatomic molecule).
Key implications of the harmonic oscillator model:
- Energy levels are equally spaced (hν0).
- Transitions are only allowed between adjacent levels (Δv=±1).
Anharmonicity
The harmonic oscillator model is an idealization. Real molecular bonds do not behave as perfect springs; they exhibit anharmonicity. As atoms move further apart, the bond weakens and eventually breaks. The potential energy curve for a real molecule is better described by the Morse potential, which is asymmetric and reflects the bond dissociation at larger interatomic distances.
Consequences of anharmonicity:
- Energy levels are not equally spaced: They become progressively closer at higher vibrational quantum numbers.
- Overtone Transitions: Transitions with Δv=±2,±3,… (e.g., v=0→v=2) become weakly allowed, observed at approximately 2ν0,3ν0, etc., but at lower intensities than fundamental transitions.
- Hot Bands: Transitions originating from excited vibrational states (v=1→v=2, v=2→v=3, etc.) become possible. These are called hot bands because their population increases with temperature.
Infrared (IR) Spectroscopy
Infrared (IR) spectroscopy measures the absorption of infrared radiation by molecules. When the frequency of the IR radiation matches the frequency of a molecular vibration, the molecule absorbs the energy and transitions to a higher vibrational state.
Principle of IR Absorption: Change in Dipole Moment
For a vibrational mode to be IR active (i.e., to absorb IR radiation), it must cause a change in the molecule’s permanent electric dipole moment during the vibration.
- Asymmetric stretching in CO2: causes a change in dipole moment, so it is IR active.
- Symmetric stretching in CO2: does not cause a change in dipole moment (dipole moments cancel), so it is IR inactive.
- Any vibration in a non-polar diatomic molecule like N2 or O2 will be IR inactive as there is no dipole moment change.
- All vibrations in a polar molecule like HCl or H2O are IR active because even symmetric movements can lead to dipole moment changes.
Instrumentation for IR Spectroscopy
Modern IR spectrometers are predominantly Fourier Transform Infrared (FTIR) spectrometers.
- Source: Generates broad-spectrum IR radiation (e.g., Globar, Nernst glower).
- Michelson Interferometer: The heart of an FTIR. It splits the IR beam into two paths, one reflected by a fixed mirror and the other by a moving mirror. The beams recombine, producing an interference pattern (interferogram) unique to the sample.
- Sample Compartment: Where the sample (gas, liquid, solid) is placed. Sample preparation techniques vary widely.
- Detector: Converts the IR signal into an electrical signal (e.g., Deuterated Triglycine Sulfate (DTGS), Mercury Cadmium Telluride (MCT)).
- Computer with Fourier Transform Software: Converts the interferogram from the time domain (detector response vs. mirror position) into a conventional spectrum (intensity vs. frequency/wavenumber).
Interpretation of IR Spectra
An IR spectrum typically plots transmittance (or absorbance) against wavenumber (cm−1). Wavenumber is proportional to energy and frequency (ν(cm−1)=ν(Hz)/c).
IR spectra are usually divided into two main regions:
- Functional Group Region (4000 – 1500 cm−1):
- Characterized by vibrations specific to particular functional groups (e.g., O-H stretch, C=O stretch, N-H stretch, C-H stretch).
- These are generally high-frequency vibrations due to lighter atoms and/or stronger bonds.
- This region is crucial for identifying the presence or absence of specific functional groups in an unknown compound.
- Fingerprint Region (1500 – 400 cm−1):
- Contains complex patterns of bending vibrations and more complex stretching vibrations.
- Highly specific to the overall molecular structure, much like a human fingerprint.
- Often difficult to assign individual bands, but invaluable for confirming identity by comparing with known spectra. Slight structural differences lead to distinct patterns in this region.
Raman Spectroscopy
Raman spectroscopy is a complementary vibrational technique based on the inelastic scattering of light. When monochromatic light (typically from a laser) interacts with a molecule, most of the light is scattered elastically (Rayleigh scattering, same frequency as incident light). However, a small fraction of the light (Raman scattering, ∼10−6 of intensity) is scattered inelastically, meaning its frequency has shifted.
Principle of Raman Scattering: Change in Polarizability
For a vibrational mode to be Raman active, it must cause a change in the molecule’s polarizability during the vibration. Polarizability refers to the ease with which the electron cloud of a molecule can be distorted by an external electric field.
- Stokes Scattering: The scattered light has a lower frequency than the incident light. This occurs when the molecule gains vibrational energy (transitions from v=0→v=1). The energy difference (ΔE) corresponds to a vibrational frequency of the molecule.
- Anti-Stokes Scattering: The scattered light has a higher frequency than the incident light. This occurs when the molecule loses vibrational energy (transitions from v=1→v=0). Anti-Stokes lines are generally weaker than Stokes lines because fewer molecules are in excited vibrational states at room temperature.
Examples:
- Symmetric stretching in CO2: causes a change in polarizability (electron cloud gets more deformable), so it is Raman active.
- Asymmetric stretching in CO2: does not cause a change in polarizability, so it is Raman inactive.
- Vibrations in non-polar diatomic molecules (N2, O2) are Raman active because their polarizability changes during vibration.
- Vibrations in polar molecules like HCl are also Raman active.
Instrumentation for Raman Spectroscopy
- Laser Source: Provides monochromatic, high-intensity light (e.g., Ar ion, He-Ne, Nd:YAG lasers).
- Sample Compartment: Samples can be in almost any state (solid, liquid, gas, even in aqueous solutions, unlike IR).
- Collection Optics: Gathers the scattered light, often at 90∘ to the incident beam, to minimize detection of the much stronger Rayleigh scattered light.
- Spectrograph/Monochromator: Disperses the scattered light by wavelength.
- Detector: Highly sensitive detectors (e.g., CCD cameras) to capture the weak Raman signal.
Comparison of IR and Raman Spectroscopy
Feature | Infrared (IR) Spectroscopy | Raman Spectroscopy |
---|---|---|
Principle | Absorption of IR radiation | Inelastic scattering of laser light |
Activity Rule | Change in permanent dipole moment | Change in polarizability |
Typical Sample State | Gas, Liquid (non-aqueous solvent), Solid (KBr pellet/Nujol) | Gas, Liquid (aqueous solution possible), Solid |
Water Sensitivity | Strong absorber, complicates aqueous samples | Weak scatterer, excellent for aqueous samples |
Symmetry & Activity | If a vibration is IR active, it may or may not be Raman active. | If a vibration is Raman active, it may or may not be IR active. |
Mutually Exclusive Rule | Applies to molecules with a center of inversion (i): vibrations that are IR active are Raman inactive, and vice-versa. | |
Types of Vibrations | Often good for polar groups, asymmetric stretches, some bending. | Often good for non-polar bonds (C=C, C≡C, S-S), symmetric stretches. |
Applications of Vibrational Spectroscopy
Vibrational spectroscopy is a versatile tool across many scientific disciplines:
- Functional Group Identification: Both IR and Raman are excellent for identifying specific functional groups (C=O, O-H, C≡N, etc.) present in a molecule based on characteristic absorption/scattering frequencies.
- Structural Elucidation: By combining information from the functional group and fingerprint regions, and using theoretical calculations, the complete structure of a molecule can often be deduced. Isotopic substitution is also very useful here.
- Qualitative and Quantitative Analysis: Used to confirm the identity of a compound (qualitative) or determine the concentration of a component in a mixture (quantitative) based on peak intensities.
- Reaction Monitoring: Real-time monitoring of chemical reactions by observing the appearance of new peaks and disappearance of reactant peaks.
- Material Characterization: Analyzing polymers, pharmaceuticals, thin films, and biological samples to understand their composition, crystallinity, and intermolecular interactions.
- Forensic Analysis: Identifying unknown substances (drugs, explosives, fibers) at crime scenes.
- Environmental Monitoring: Detecting pollutants in air or water.
Conclusion
Vibrational spectroscopy, through its two powerful techniques, Infrared and Raman, provides an invaluable window into the dynamic world of molecular vibrations. By probing how molecules absorb or scatter light at specific frequencies, we gain detailed insights into their fundamental structure, bonding, and chemical environment. From identifying functional groups to unraveling complex molecular architectures and even monitoring chemical processes in real-time, vibrational spectroscopy remains an indispensable tool for chemists, biologists, materials scientists, and physicists alike. Its complementary nature (IR and Raman) often means that together, they provide a more complete picture of a molecule’s vibrational behavior than either technique alone.
Vibrational Spectroscopy: Multiple Choice Questions
Instructions: Choose the best answer for each question. Explanations are provided after each question.
1. Which region of the electromagnetic spectrum is primarily used in Infrared (IR) spectroscopy? a) Ultraviolet b) Visible c) Microwave d) Infrared e) X-ray
Explanation: IR spectroscopy deals with molecular vibrations, whose energy levels correspond to frequencies found in the infrared region of the electromagnetic spectrum.
2. What is the total number of degrees of freedom for a non-linear molecule with N atoms? a) 3N−5 b) 3N−6 c) 3N d) N e) 3
Explanation: For non-linear molecules, 3 degrees of freedom are for translation and 3 for rotation, leaving 3N−6 for vibrations.
3. Which type of vibration involves a rhythmic movement along the bond axis, increasing and decreasing the bond length? a) Bending b) Scissoring c) Twisting d) Stretching e) Wagging
Explanation: Stretching vibrations directly change the distance between bonded atoms.
4. For a vibrational mode to be IR active, what fundamental requirement must be met? a) The molecule must be non-polar. b) It must involve a change in the molecule’s permanent electric dipole moment. c) It must cause a change in the molecule’s polarizability. d) The vibration must be symmetric. e) The molecule must have a center of inversion.
Explanation: IR absorption occurs when a molecular vibration causes an oscillating electric dipole moment that can interact with the oscillating electric field of the IR radiation.
5. Which of the following molecules would be IR inactive for its symmetric stretching mode? a) HCl b) H2O c) CO d) CO2 e) NH3
Explanation: In the symmetric stretching of linear CO2, both C=O bonds stretch and compress equally and oppositely, resulting in no net change in the molecule’s dipole moment.
6. The harmonic oscillator model predicts that vibrational energy levels are: a) Unequally spaced b) Equally spaced c) Dependent on temperature only d) Non-quantized e) Zero for all molecules
Explanation: In the simple harmonic oscillator model, the potential energy well is perfectly parabolic, leading to evenly spaced vibrational energy levels.
7. What phenomenon describes the deviation of real molecular bonds from the ideal harmonic oscillator behavior? a) Degeneracy b) Resonance c) Anharmonicity d) Isotopic effect e) Doppler effect
Explanation: Anharmonicity refers to the non-ideal behavior of molecular vibrations where the restoring force is not perfectly proportional to the displacement, especially at larger displacements.
8. Which instrument component is unique to a Fourier Transform Infrared (FTIR) spectrometer compared to a dispersive IR spectrometer? a) IR source b) Sample compartment c) Detector d) Michelson Interferometer e) Computer
Explanation: The Michelson interferometer is the core optical component of an FTIR spectrometer, responsible for generating the interferogram.
9. What is the typical wavenumber range for the “functional group region” in an IR spectrum? a) 400−1500 cm−1 b) 1500−4000 cm−1 c) 4000−10000 cm−1 d) 0−400 cm−1 e) 100−1000 cm−1
Explanation: The region from approximately 1500 to 4000 cm−1 is where characteristic stretching vibrations of common functional groups are observed.
10. What is the main principle behind Raman spectroscopy? a) Absorption of visible light b) Elastic scattering of X-rays c) Inelastic scattering of monochromatic light d) Emission of ultraviolet radiation e) Resonance fluorescence
Explanation: Raman spectroscopy measures the small frequency shifts in light that has been inelastically scattered by molecules due to their vibrational transitions.
11. For a vibrational mode to be Raman active, what fundamental requirement must be met? a) It must involve a change in the molecule’s permanent electric dipole moment. b) The molecule must be polar. c) It must cause a change in the molecule’s polarizability. d) The vibration must be asymmetric. e) The molecule must not have a center of inversion.
Explanation: Raman activity is governed by whether a vibration causes a change in how easily the molecule’s electron cloud can be distorted by an electric field (polarizability).
12. In Raman spectroscopy, what type of scattered light has a lower frequency than the incident light? a) Rayleigh scattering b) Anti-Stokes scattering c) Stokes scattering d) Fluorescence e) Phosphorescence
Explanation: Stokes scattering occurs when the molecule gains energy from the photon, resulting in the scattered photon having less energy and thus a lower frequency.
13. The mutually exclusive rule in vibrational spectroscopy states that for molecules with a center of inversion (i): a) All vibrations are both IR and Raman active. b) No vibrations are IR or Raman active. c) Vibrations that are IR active are Raman inactive, and vice-versa. d) Only symmetric vibrations are active. e) Only bending vibrations are active.
Explanation: If a molecule has a center of inversion, any vibration that causes a change in dipole moment (IR active) cannot simultaneously cause a change in polarizability (Raman active), and vice-versa.
14. Which of the following molecules would be Raman active for its symmetric stretching mode, but IR inactive? a) HCl b) H2O c) CO2 d) NH3 e) CH4
Explanation: Linear CO2 has a center of inversion. Its symmetric stretch changes polarizability but not dipole moment, making it Raman active and IR inactive.
15. What is the purpose of a laser source in Raman spectroscopy? a) To heat the sample. b) To provide monochromatic, high-intensity incident light. c) To absorb scattered light. d) To generate infrared radiation. e) To induce a dipole moment in the molecule.
Explanation: Lasers are used in Raman spectroscopy because they provide the intense, single-wavelength light needed for the weak inelastic scattering phenomenon.
16. What does the term “fingerprint region” in an IR spectrum refer to? a) The region used for quantitative analysis only. b) The region where only stretching vibrations occur. c) The region below 1500 cm−1 that is highly specific to the overall molecular structure. d) The region where all functional groups absorb. e) The region influenced by ambient moisture.
Explanation: The fingerprint region is highly complex and unique for each molecule, allowing for definitive identification by comparison with reference spectra.
17. If a molecule has N atoms and is linear, how many vibrational normal modes does it have? a) 3N b) 3N−5 c) 3N−6 d) N−2 e) N−1
Explanation: Linear molecules have 3 translational and 2 rotational degrees of freedom, leaving 3N−5 for vibrations.
18. What is a “hot band” in vibrational spectroscopy? a) A transition originating from the ground vibrational state. b) A transition with Δv=±2. c) A transition originating from an excited vibrational state (v>0). d) A highly intense absorption peak. e) A band observed only at very low temperatures.
Explanation: Hot bands appear when molecules in already excited vibrational states absorb energy and transition to even higher states. Their intensity increases with temperature because more excited states are populated.
19. What does the force constant (k) in the harmonic oscillator model represent? a) The bond length b) The mass of the atoms c) The stiffness of the bond d) The dipole moment e) The number of vibrational modes
Explanation: A higher force constant implies a stiffer, stronger bond that is harder to stretch or compress.
20. Which of the following vibrational modes is typically found in the functional group region of an IR spectrum? a) C-H bending (e.g., in-plane rock) b) C=C stretch (aromatic ring) c) O-H stretch d) C-C skeletal vibrations e) Complex bending motions of large molecules
Explanation: The O-H stretch is a characteristic high-frequency vibration that falls within the functional group region.
21. Why are anti-Stokes lines typically weaker than Stokes lines in a Raman spectrum? a) They are forbidden by selection rules. b) Fewer molecules are in excited vibrational states (v=1) at room temperature. c) The incident laser light is not strong enough. d) They occur at higher frequencies. e) The detector is less sensitive at higher frequencies.
Explanation: Anti-Stokes scattering requires the molecule to lose energy from an already excited vibrational state (v=1). According to Boltzmann distribution, the population of excited states is lower than the ground state (v=0) at typical temperatures.
22. Which of these properties is NOT determined by vibrational spectroscopy? a) Functional groups present b) Bond lengths c) Presence of isotopic variants d) Molecular symmetry e) Intermolecular interactions
Explanation: While bond stiffness (force constant) can be estimated, precise bond lengths are more accurately determined by rotational or X-ray crystallography techniques, as vibrational frequencies are also dependent on reduced mass.
23. What is the advantage of using aqueous solutions as samples in Raman spectroscopy compared to IR? a) Water has a very strong Raman signal. b) Water is a weak Raman scatterer, minimizing interference. c) Raman spectrometers are more robust to water damage. d) Aqueous solutions fluoresce strongly in Raman. e) Water significantly enhances Raman signals.
Explanation: Water is a weak Raman scatterer, meaning its own signal doesn’t heavily overlap or obscure the signals from the analyte, making it an excellent solvent for Raman studies. In contrast, water is a strong IR absorber.
24. The fundamental vibrational frequency of a bond is primarily dependent on its: a) Molecular weight and polarity b) Bond length and dipole moment c) Force constant and reduced mass d) Electron configuration and rotational constant e) Temperature and pressure
Explanation: The harmonic oscillator model equation (ν0=2π1μk) directly shows the dependence on force constant (k) and reduced mass (μ).
25. If a vibrational transition occurs from v=0 to v=2, this is known as a(n): a) Fundamental transition b) Hot band c) Overtone d) Combination band e) Fermi resonance
Explanation: A transition where the vibrational quantum number changes by more than 1 (Δv>1) is called an overtone.
26. Which type of bending vibration involves a group of atoms moving back and forth in the same plane? a) Wagging b) Twisting c) Scissoring d) Rocking e) Asymmetric bending
Explanation: Rocking describes the movement of a group of atoms within the same plane, like a rocking chair.
27. What happens to the vibrational frequency of a bond if a heavier isotope replaces one of the atoms involved in the bond? a) It increases. b) It decreases. c) It remains the same. d) It depends on the bond strength. e) It becomes zero.
Explanation: Replacing an atom with a heavier isotope increases the reduced mass (μ) of the vibrating system. Since frequency is inversely proportional to the square root of reduced mass, the frequency will decrease.
28. What is the primary function of the Michelson Interferometer in FTIR spectroscopy? a) To disperse light into its component frequencies. b) To hold the sample in place. c) To create an interference pattern (interferogram) containing all frequency information. d) To detect infrared radiation. e) To filter out unwanted radiation.
Explanation: The interferometer generates an interferogram by varying the path difference between two beams of light, which encodes the spectral information.
29. The “fingerprint region” of an IR spectrum is particularly useful for: a) Identifying basic functional groups like C=O or O-H. b) Performing quantitative analysis with high precision. c) Distinguishing between very similar compounds. d) Studying electronic transitions. e) Analyzing samples in aqueous solutions.
Explanation: The complex and unique pattern of peaks in the fingerprint region acts as a molecular “signature,” making it excellent for confirming the identity of a compound or distinguishing between isomers.
30. Which of the following is an example of an application where vibrational spectroscopy is used for real-time monitoring? a) Determining the exact bond length of a molecule. b) Identifying a functional group in an unknown sample. c) Tracking the progress of a chemical reaction. d) Measuring the concentration of a component in a mixture. e) Analyzing the isotopic composition of a sample.
Explanation: By observing the change in intensity of reactant and product peaks over time, vibrational spectroscopy can effectively monitor the kinetics and progression of a chemical reaction.
31. In the harmonic oscillator model, what is the selection rule for vibrational transitions? a) Δv=0 b) Δv=±1 c) Δv=±2 d) Δv=±1,±2 e) Any Δv is allowed.
Explanation: For a pure harmonic oscillator, only transitions between adjacent energy levels are allowed.
32. Which type of stretching vibration involves one bond lengthening while the other bond shortens? a) Symmetric stretching b) Scissoring c) Asymmetric stretching d) Rocking e) Wagging
Explanation: Asymmetric stretching describes the opposing motion of two bonds in a vibrational mode.
33. What is the relationship between wavenumber and frequency? a) Wavenumber is directly proportional to frequency. b) Wavenumber is inversely proportional to frequency. c) Wavenumber is independent of frequency. d) Wavenumber is proportional to the square of frequency. e) Wavenumber is equal to frequency.
Explanation: Wavenumber (νˉ) and frequency (ν) are related by νˉ=ν/c, where c is the speed of light. Thus, they are directly proportional.
34. Why is water a problematic solvent for IR spectroscopy? a) It is highly flammable. b) It has a very low boiling point. c) It has strong IR absorption bands that overlap with many analytes. d) It causes fluorescence. e) It reacts with most IR cells.
Explanation: Water has very strong and broad absorption bands across much of the mid-infrared region, which can obscure the signals from the sample being studied.
35. If a molecule has a center of inversion, and a particular vibrational mode is IR active, what can be said about its Raman activity? a) It is also Raman active. b) It is Raman inactive. c) Its Raman activity depends on temperature. d) Its Raman activity depends on the solvent. e) Its Raman activity cannot be determined.
Explanation: According to the mutually exclusive rule, for molecules with a center of inversion, if a mode is IR active, it must be Raman inactive.
36. Overtones in a vibrational spectrum appear at approximately integer multiples of the fundamental frequency due to: a) Hot bands b) Degeneracy c) Anharmonicity d) Isotopic substitution e) Fermi resonance
Explanation: Anharmonicity causes the energy levels to be slightly unevenly spaced, allowing for weaker transitions to higher vibrational levels (overtones) that are close to integer multiples of the fundamental.
37. Which of the following is typically a high-frequency vibration in the functional group region? a) C-C single bond stretch b) C-H stretch c) C-O single bond stretch d) C-Cl stretch e) C-N single bond stretch
Explanation: C-H stretches typically occur around 2800−3300 cm−1, which is in the high-frequency part of the functional group region.
38. Which technique would be more suitable for studying the symmetric stretch of a non-polar diatomic molecule like N2? a) IR spectroscopy b) UV-Vis spectroscopy c) Raman spectroscopy d) NMR spectroscopy e) Mass spectrometry
Explanation: N2 has no permanent dipole moment, so its vibrations are IR inactive. However, its symmetric stretch causes a change in polarizability, making it Raman active.
39. What type of vibration involves a group of atoms rotating around a bond, with one atom moving up and another down relative to a plane? a) Rocking b) Wagging c) Scissoring d) Twisting e) Symmetric stretching
Explanation: Twisting involves a rotation of a part of the molecule around a bond, leading to out-of-plane motion where parts move in opposite directions.
40. The energy difference between vibrational levels in a real molecule is generally: a) Constant for all levels. b) Increasing with increasing vibrational quantum number. c) Decreasing with increasing vibrational quantum number. d) Zero at room temperature. e) Only dependent on the molecule’s dipole moment.
Explanation: Due to anharmonicity, the spacing between vibrational energy levels decreases as the vibrational quantum number increases, leading to convergence at higher energies.